Where is Seymour located?

Seymour is located in United States. It is positioned in "America/Indiana/Indianapolis" time zone (GMT-4 ) with current time of 07:23 AM, Tuesday (difference from your time zone: hours). Seymour is populated place in Indiana in Jackson County with population of ∼17.5 thousand.

Geographical position

Latitude: 38.95922°

5675 km

4332 km

38° 57' 33.192" North

Longitude: -85.89025°

7114 km

7715 km

85° 53' 24.9" West

Elevation: 185 m

185 m

185 m ≈ 607 feet

Seymour on map

Distances from Seymour

Places around Seymour sort by population

Columbus 27.1 km Lowell 33 km Scottsburg 32.1 km North Vernon 23.6 km Austin 23.4 km Country Squire Lakes 18.6 km Brownstown 15.9 km Hope 39.7 km Crothersville 18.1 km Westport 36.5 km

Seymour

40 km

Columbus

Lowell

Scottsburg

North Vernon

Austin

Country Squire Lakes

Brownstown

Hope

Crothersville

Westport

Distance from largest cities in United States sort by population

New York City 1032 km Los Angeles 2927 km Chicago 354 km Brooklyn 1036 km Borough of Queens 1046 km Houston 1341 km Philadelphia 927 km Manhattan 1037 km Phoenix 2419 km The Bronx 1046 km

Seymour

2927 km

New York City

Los Angeles

Chicago

Brooklyn

Borough of Queens

Houston

Philadelphia

Manhattan

Phoenix

The Bronx

Distance from cities in world

New York City 1032 km Los Angeles 2927 km London 6464 km Rio de Janeiro 8187 km Moscow 8211 km Tokyo 10487 km Dubai 11825 km Hong Kong 12892 km Johannesburg 13799 km Sydney 14957 km

Seymour

14957 km

New York City

Los Angeles

London

Rio de Janeiro

Moscow

Tokyo

Dubai

Hong Kong

Johannesburg

Sydney

Sources, notes:
• Map is powered by openstreetmap.org.
• Geographic location info from www.geonames.org database.
• Population data is only approximately value, it may be out of date.
• Distance calculator between two coordinates is powered by PHP with rounding precision of 0.1 km (or 1 km for longer distances), source code can be found at 1km.net site.